E-Math - Trigonometry - 3 Dimension Problems - Open Door
a) the distance CE,
Since AD=BC=BE (Length of door)
As the triangle is NOT a Right Angle we will use Cosine Rule
c2=a2+b2−2abCosCx2=12+12−2(1)(1)Cos38ox2=0.42398x=0.65113=0.651m(3sig)
b) the length AE,
Since it is a rectangular door. Angle ABE is 90 degrees.
We use Pythagoras Theorem.
c2=a2+b2y2=22+(1)2c2=5c=2.2361=2.24m(3sig)
c) ∠CAE.
Use the values found in a) and b)
AE=AC=2.1033, EC=0.65113
Since the triangle is NOT a Right Angle,
we will use Cosine Rule.
c2=a2+b2−2abCosC0.651132=2.23612+2.23612−2(2.2361)(2.2361)CosC0.42397=10.000−10.000CosC10.000CosC=10.000−0.42397CosC=9.5760210.000C=Cos−10.95760C=16.74o=16.7o
When a Triangle is a Right Angle, use Sine, Cosine , Tangent and Pythagoras Theorem.
But when a Triangle is NOT a Right Angle, use Sine Rule and Cosine Rule (In the Formula List of the O level E-Math Exam Paper).
I suggest that you draw out the triangle to find the unknown side /angle as 3-D figure can be
visually confusing at times.
Additional Math (A-Maths) and Math (E-Math) Tutor in Woodlands, Chua Chu Kang,
Sembawang, Bukit Panjang, Yishun and Johor Bahru.
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