E-Math - Trigonometry - 3 Dimension Problems - Open Door

E-Math - Trigonometry - 3 Dimension Problems - Open Door 




















a) the distance CE,

Since AD=BC=BE (Length of door)



As the triangle is NOT a Right Angle we will use Cosine Rule

c2=a2+b22abCosCx2=12+122(1)(1)Cos38ox2=0.42398x=0.65113=0.651m(3sig)



b) the length AE,


Since it is a rectangular door. Angle ABE is 90 degrees.
We use Pythagoras Theorem.

c2=a2+b2y2=22+(1)2c2=5c=2.2361=2.24m(3sig)







c) CAE.

Use the values found in a) and b)
AE=AC=2.1033, EC=0.65113

Since the triangle is NOT a Right Angle,
we will use Cosine Rule.
c2=a2+b22abCosC0.651132=2.23612+2.236122(2.2361)(2.2361)CosC0.42397=10.00010.000CosC10.000CosC=10.0000.42397CosC=9.5760210.000C=Cos10.95760C=16.74o=16.7o



When a Triangle is a Right Angle, use Sine, Cosine , Tangent and Pythagoras Theorem.
But when a Triangle is NOT a Right Angle, use Sine Rule and Cosine Rule (In the Formula List of the O level E-Math Exam Paper).

I suggest that you draw out the triangle to find the unknown side /angle as 3-D figure can be
visually confusing at times.


Additional Math (A-Maths) and Math (E-Math) Tutor in Woodlands, Chua Chu Kang,
Sembawang, Bukit Panjang, Yishun and Johor Bahru.

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About Unknown

I created this Blog after my students told me that there is very little information about how to solve GCE O Level Math and Additional Math (A-Math) questions on the internet. Even if they manage to find, the solution were for very basic questions. I am a Full-time Math Tutor in Singapore. I tutor mainly in Northern Singapore (Woodlands, Chua Chu Kang, Bukit Panjang, Yishun and Sembawang). I also tutor in Johor Bahru.
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