A-Math - Trigonometry - Trigonometric Identities (5)
\(\frac{{3 - 6{{\cos }^2}x}}{{\sin x - \cos x}} = 3(\sin x + \cos x)\)
Topic: Trigonometry |
We will start manipulating from the side that looks more complicated,
in this case,it is the left hand side (LHS). If you look at the question, you
realize that \(3 - 6{\cos ^2}x\) looks somewhat similar to the double angle
formula \(2{\cos ^2}x - 1 = \cos 2x\) and we can change the numerator
\(2{\cos ^2}x - 1 = \cos 2x = {\sin ^2}x - {\cos ^2}x\) to cancel out
\(\sin x - \cos x\) in the denominator.
If you practice enough question on proving trigonometric identities, you
will be able to look at the question and come up with a plan to manipulate
rather quickly, it is from experience and EXPERIENCE=PRACTICE.
Additional Math (A-Maths) and Math (E-Math) Tutor in Woodlands, Chua Chu Kang,
Sembawang, Bukit Panjang, Yishun and Johor Bahru.
Blogger Comment
Facebook Comment